Class ErfPrecision
java.lang.Object
nl.tudelft.simulation.jstats.math.ErfPrecision
Erf function precision test.
Copyright (c) 2021-2024 Delft University of Technology, Jaffalaan 5, 2628 BX Delft, the Netherlands. All rights reserved. See for project information DSOL Manual. The DSOL project is distributed under a three-clause BSD-style license, which can be found at DSOL License.
- Author:
- Alexander Verbraeck
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Method Summary
Modifier and TypeMethodDescription(package private) static double
erf
(double z) Calculate erf(z), where three different algorithms are used for small, medium, and large values.(package private) static double
erfBig
(double z) Calculate erf(z) for large values using the Taylor series:
erf(z) = 1 - (exp(-z2) / √π) Σ [ (-1)n (2n - 1)!!(package private) static double
erfInv
(double y) Approximates erf-1(p) using a Taylor series.
The Taylor series for erf-1(z) is:
erf-1(p) = √π Σ [ 1/2 p + 1/24 π p3 + 7/960 π2 p5 + 127/80640 π3 p7 + ... ]
See https://mathworld.wolfram.com/InverseErf.html.(package private) static double
erfSmall
(double z) The Taylor series for erf(z) for abs(z) < 0.5 that is used is:
erf(z) = (exp(-z2) / √π) Σ [ 2z2n + 1 / (2n + 1)!!](package private) static double
erfTaylor
(double z) Calculate erf(z) using the Taylor series:
erf(z) = (2/√π) (z - z3/3 + z5/10 - z7/42 + z9/216 - ...)
The factors are given by https://oeis.org/A007680, which evaluates to a(n) = (2n+1)n!.(package private) static double
inverseErf
(double y) Calculate based on http://www.naic.edu/~jeffh/inverse_cerf.c code.static void
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Method Details
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erf
static double erf(double z) Calculate erf(z), where three different algorithms are used for small, medium, and large values.- Parameters:
z
- double; the value to calculate erf(z) for- Returns:
- double; erf(z)
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erfSmall
static double erfSmall(double z) The Taylor series for erf(z) for abs(z) < 0.5 that is used is:
erf(z) = (exp(-z2) / √π) Σ [ 2z2n + 1 / (2n + 1)!!]
where the !! operator is the 'double factorial' operator which is (n).(n-2)...8.4.2 for even n, and (n).(n-2)...3.5.1 for odd n. See https://mathworld.wolfram.com/Erf.html formula (9) and (10). This function would work well for z < 0.5.- Parameters:
z
- double; the parameter- Returns:
- double; erf(x)
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erfBig
static double erfBig(double z) Calculate erf(z) for large values using the Taylor series:
erf(z) = 1 - (exp(-z2) / √π) Σ [ (-1)n (2n - 1)!! z-(2n + 1) / 2n]
where the !! operator is the 'double factorial' operator which is (n).(n-2)...8.4.2 for even n, and (n).(n-2)...3.5.1 for odd n. See https://mathworld.wolfram.com/Erf.html formula (18) to (20). This function would work well for z > 3.7.- Parameters:
z
- double; the argument- Returns:
- double; erf(z)
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erfTaylor
static double erfTaylor(double z) Calculate erf(z) using the Taylor series:
erf(z) = (2/√π) (z - z3/3 + z5/10 - z7/42 + z9/216 - ...)
The factors are given by https://oeis.org/A007680, which evaluates to a(n) = (2n+1)n!. See https://en.wikipedia.org/wiki/Error_function. This works pretty well on the interval [0.5,3.7].- Parameters:
z
- double; the argument- Returns:
- double; erf(z)
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erfInv
static double erfInv(double y) Approximates erf-1(p) using a Taylor series.
The Taylor series for erf-1(z) is:
erf-1(p) = √π Σ [ 1/2 p + 1/24 π p3 + 7/960 π2 p5 + 127/80640 π3 p7 + ... ]
See https://mathworld.wolfram.com/InverseErf.html.
The factors are given by https://oeis.org/A002067 which evaluates to and https://oeis.org/A122551- Parameters:
y
- double; the cumulative probability to calculate the inverse error function for- Returns:
- erf-1(y)
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inverseErf
static double inverseErf(double y) Calculate based on http://www.naic.edu/~jeffh/inverse_cerf.c code.- Parameters:
y
- double; value to calculate erf-1(y) for- Returns:
- double; erf-1(x)
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main
- Parameters:
args
- not used
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